60x^2+1500x-4000=0

Solution for 60x^2+1500x-4000=0 equation:

60x^2+1500x-4000=0

a = 60; b = 1500; c = -4000;
Δ = b2-4ac
Δ = 15002-4·60·(-4000)
Δ = 3210000
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:
$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}$
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}$

The end solution:

$\sqrt{\Delta}=\sqrt{3210000}=\sqrt{10000*321}=\sqrt{10000}*\sqrt{321}=100\sqrt{321}$
$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(1500)-100\sqrt{321}}{2*60}=\frac{-1500-100\sqrt{321}}{120}
$
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(1500)+100\sqrt{321}}{2*60}=\frac{-1500+100\sqrt{321}}{120}
$